the ratio between the three quadrilateral is 3 : 5 : 9, the value of the fourth angle of the quadrilateral is 71 degree. what is the difference between the largest and the smallest angle of the quadrilateral
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Answered by
4
Answer:
Let the common multiple be x
The four angles of quadrilateral be 3x, 5x, 9x, 71
Sum of all angles of quadrilateral is 360°
Hence,
3x + 5x + 9x + 71 = 360
17x = 360 - 71
17x = 289
x = 17
The angles of quadrilateral are:
3x = 3 × 17 = 51
5x = 5 × 17 = 105
9x = 9 × 17 = 153
Largest angle = 153°
Smallest angle = 51°
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Answered by
3
102°
Step-by-step explanation:
Let us assume that in aquadrilateral ABCD the three angles of a quadrilateral are 3x,5x,9x,and Fourth angle is 71°.
We know that,Sum of angles of a quadrilateral is 360°.
⇒∠A+∠B+∠C+∠D=360°
⇒3x+5x+9x+71°=360°
⇒ 17x+71°=360°
⇒17x=360°-71°
⇒17x=289°
⇒x=17°
So that,∠°
∠°
∠°
Now,we have to find
∠C-∠D=153°-51°
=102°
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