Question

The ratio between two numbers is 4:7. If 8 is added to each number, the ratio becomes 3:5. Find the numbers.

Answer 1

Answer:

see the question explanation and then u will able to solve it..hope it helps

Step-by-step explanation:

let the numbers be 4x and 7x

8 is to be added to each of numbers=

4x+8 and 7x+8

now,

4x+8=3x    [as 3:5 will become 3x and 5x]

4x-3x=8

x=8 [i equation]

7x+8=5x

7x-5x=8

2x=8

x=4[ii equation]

4x will become (4x8)=32

7x will become(7x4)=28

Answer 2

Answer :

The required numbers are 64 and 112

Given :

• The ratio between two numbers is 4:7
• If 8 is added to each number , the ratio becomes 3:5.

To Find :

• The numbers

Solution :

Let us consider the numbers be x and y respectively.

According to question

$\sf \implies \dfrac{x}{y} = \dfrac{4}{7}\\\\ \sf \implies x = \dfrac{4}{7}y....... (1)$

Again ,

$\sf \implies \dfrac{x + 8}{y+8} = \dfrac{3}{5}\\\\ \sf \implies 5(x + 8)=3 (y+8) \\\\ \sf Putting \: the \: of \: x \: from \: (1)\\\\ \sf \implies 5 (\dfrac{4}{7}y + 8)=3 (y+ 8) \\\\ \sf \implies \dfrac{5(4y + 56)}{7}= 3y + 24 \\\\ \sf \implies 20y + 280 = 21y + 168 \\\\ \sf \implies 21y - 20y = 280 -168 \\\\ \sf \implies y = 112$

Using the value of y in (1) we have : $\sf \implies x = \dfrac{4}{7}\times 112\\\\ \sf\implies x = 4\times 16 \\\\ \sf \implies x = 64$