Question

the ratio in the ages of a, b,& c six years before was 2:3:5 if the sum of their present ages is 168 find their present ages solve the problem

Answer 1

Sum of ratio 2+3+5= 10.
Then
A= 2/10x 168=168/5
B=3/10x168=252/5
C=5/10x168=2100/5
A = 168/5
B=252/5
C= 2100/5

Answer 2

ratio of ages meaning before 6yrs their ages were

a= 2x
b=3x
c=5x

So after 6yrs

a= 2x+6
b=3x+6
c=5x+6

sum of their present ages = 168
2x+6 + 3x+6 + 5x+6 = 168
10x + 18 = 168
10x = 168 - 18
10x = 158
x = 158 / 10
x = 15.8

a = 2x+6 = (2×15.8) + 6 = 37.6
b = 3x+6 = (3×15.8) + 6 = 53.4
c = 5x+6 = (5×15.8) + 6 = 85