the ratio in the ages of a b and c 6 years before was 2 ratio 3 ratio 5 if the sum of their present ages is 168 find their ages
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ratio of their previous ages = 2:3:5
let their ages = 2x,3x,5x
their present ages are
2x+6,3x+6,5x+6
given sum of their present ages is 168
so, 2x+6+3x+6+5x+6= 168
10x+18=168
10x=150
x=15
now,
a=2x+6=36yrs
b=3x+6=51yrs
c=5x+6=81yrs
thank you
if it is wrong please excuse me hope it helped you
let their ages = 2x,3x,5x
their present ages are
2x+6,3x+6,5x+6
given sum of their present ages is 168
so, 2x+6+3x+6+5x+6= 168
10x+18=168
10x=150
x=15
now,
a=2x+6=36yrs
b=3x+6=51yrs
c=5x+6=81yrs
thank you
if it is wrong please excuse me hope it helped you
sidhu79:
sorry if it is wrong
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