Question

The ratio in the ages of A, B and C six years before was 2:3:5 If the sum of their present ages is 168 years, find their ages separately.

Answer 1

let the age of A- 2x+6

let the age of B -3x+6

let the age of C -5x+6

sum of ages of A,B,C=(2x+6+3x+6+5x+6)=168

• 10x+18=168
• 10x=168-18                  transferring +18 from LHS to RHS
• 10x=150

• x=150÷10
• x=15

age of A=2x+6 =2×15+6=36

age of B=3x+6= 3×15+6=51

age of C=5x=6=5×15+6=81

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