the ratio in which the line 3x+4y-7=0 divides the line joining the points (1,2) (2,3) is _
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Let the point (x,y) divides AB in the ratio k:1. By section formula,x = (2k+1)/(k+1) , y = (7k+3)/(k+1) Now, this point also lies on the given line so it would satisfy the equation 3x+y-9=0Therefore,3(2k+1) + (7k+3) -9(k+1) = 0k = 3/4Hence, the required ratio is 3:4.
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