x2-7x+12 please helppp
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Answered by
1
x²-7x+12=0
x²-4x-3x+12=0
x(x-4)-3(x-4)=0
(x-3)(x-4)=0
x=3,4
x²-4x-3x+12=0
x(x-4)-3(x-4)=0
(x-3)(x-4)=0
x=3,4
Answered by
1
x^2 - 3x - 4x +12
x(x-3) -4(x-3)
(x-3)(x-4)
hope it helps u..
x(x-3) -4(x-3)
(x-3)(x-4)
hope it helps u..
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