Question

The ratio in which the line segment joining the points (3,-4) and (-5,6) is divided along the x axis

Answer 1

Let C(x,0) be the point dividing line segment AB in the ratio m:n

Using formula- The point which divides a line segment AB in the ratio m:n is given by [(mx₂+nx₁)/(m+n),(my₂+ny₁)/(m+n)] whre A=(x₁,y₁),B=(x₂,y₂)

So, y-coordinate of  C is given by [m*6 + n*(-4) ]/(m+n) = 0

i.e m:n = 4:6 = 2:3

and x-coordinate of C is x= [2*(-5) + 3*3]/5 = 1/5