Question

The ratio in which the X-axis divides
the line segment joining (3, 6) and
(12, -3) is​

Answer 1

Answer:

Step-by-step explanation:

The diagram is required but diagram is easy to be drawn.

Let A(3,6) ,B (12,-3 )

Let X-axis divide the line AB in the ratio k:1

By using section formula

(mx2+nx1/m+n) , (my2+ny1/m+n)

Consider a point Q

Coordinates of Q = (6k+3/k+1), (-3k+12/k+1)

Equating coordintes of Y to 0

-3k+12/k+1=0

-3k+12 =0

-3k =-12

k=4

Hence the required ratio is 5:1

Answer 2

Answer:

5:1

Step-by-step explanation:

Let A(3,6) ,B (12,-3 )

Let X-axis divide the line AB in the ratio k:1

By using section formula

(mx2+nx1/m+n) , (my2+ny1/m+n)

Consider a point Q

Coordinates of Q = (6k+3/k+1), (-3k+12/k+1)

Equating coordintes of Y to 0

-3k+12/k+1=0

-3k+12 =0

-3k =-12

k=4

Hence the required ratio is 5:1

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