The ratio of 7th to 3rd term of an AP is 12:5 find the ratio of the 13th and 4th term
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let the first term is a and common difference is d
then
3rd term is a+2d
7th term =a+6d
ATQ
(a+6d)/(a+2d) =12/5
5a+30d=12a+24d
7a=6d
a=6d/7
ratio of 13th and 4th term is
(a+12d)/(a+3d)
put value of a then
90d×7/27d×7
=10/3
ok
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Answer: 15 : 9
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