Question

The ratio of A's age 3 years ago and B's age 5
years ago was 4 : 5. If A is 4 years younger

than B then what is the present age of B?​

Answer 1

Step-by-step explanation:

1. let n be the common factor in the given ratio
2. age of A 3 years ago=4n
3. age of B 3 years ago=5n
4. as a is 4 years younger than B so the age of A three years ago=5n-4
5. now we can equate the values
6. we have,

4n=5n-4

n=4

1. age of B three years ago=5n=5x4=20
2. required present age of B=20+3=23

I hope this answer would be helpful for you please give it a brainliest mark if it helped u

Answer 2

Answer:

15

Step-by-step explanation:

3 years ago age of A is 4x.

Present age of A is 4x+3.

5 years ago age of B is 5x.

Present age of B is 5x+5.

Age difrence between A and B is 4

Hence 5x+5-(4x+3)=4

5x+5-4x-3=4

X+2=4

X=2.

Present age of B =5x+5

=5*2+5

=10+5

=15.