Question

the ratio of a two digit number to the number obtained by reversing it's digits is 4:7​

Answer 1

Answer:

Siddhartharao77Maths AryaBhatta

Let x be the required two-digit number at ten's place.

Let y be the required two-digit number at one's place.

Therefore the decimal expansion is 10x+y.

Given that the difference between the digits of the number is 3.

x - y = 3 

y = x + 3 ------ (1)

Given that the ratio between a two-digit number and number obtained by reversing the digits is 4:7.

10x + y/10y + x = 4/7

7(10x + y) = 4(10y + x)

70x + 7y = 40y + 4x

66x = 33y

66x = 33(x+3)

66x = 99x + 99

33x = 99

x = 3.

Substitute x = 3 in (1) we get

y = x + 3

y = 6.

Therefore the required two-digit number is 36.

verification:

10x + y/10y + x = 4/7

10(3) + 6/10(6) + 3 = 4/7

30 + 6/60 + 3 = 4/7

36/63 = 4/7

4/7 = 4/7