The ratio of acceleration due to gravities at the surface of two planets of radii R, and R2 is (Assume densities of two planets are same)
(R2/R1)2
(r1/r2)2
r1/r2
r2/r1
Answers
ANSWER
ANSWERa
ANSWERa 1
ANSWERa 1
ANSWERa 1 =
ANSWERa 1 = r
ANSWERa 1 = r 1
ANSWERa 1 = r 12
ANSWERa 1 = r 12 GM
ANSWERa 1 = r 12 GM 1
ANSWERa 1 = r 12 GM 1
ANSWERa 1 = r 12 GM 1 ,a
ANSWERa 1 = r 12 GM 1 ,a 2
ANSWERa 1 = r 12 GM 1 ,a 2
ANSWERa 1 = r 12 GM 1 ,a 2 =
ANSWERa 1 = r 12 GM 1 ,a 2 = r
ANSWERa 1 = r 12 GM 1 ,a 2 = r 2
ANSWERa 1 = r 12 GM 1 ,a 2 = r 22
ANSWERa 1 = r 12 GM 1 ,a 2 = r 22
ANSWERa 1 = r 12 GM 1 ,a 2 = r 22GM
ANSWERa 1 = r 12 GM 1 ,a 2 = r 22GM 2
a
a 1
a 1
a 1 =
a 1 = r
a 1 = r 1
a 1 = r 12
a 1 = r 12Gρ
a 1 = r 12Gρ 1
a 1 = r 12Gρ 1
a 1 = r 12Gρ 13
a 1 = r 12Gρ 134
a 1 = r 12Gρ 134
a 1 = r 12Gρ 134 πr
a 1 = r 12Gρ 134 πr 1
a 1 = r 12Gρ 134 πr 13
a 1 = r 12Gρ 134 πr 13
a 1 = r 12Gρ 134 πr 13 ,a
a 1 = r 12Gρ 134 πr 13 ,a 2
a 1 = r 12Gρ 134 πr 13 ,a 2
a 1 = r 12Gρ 134 πr 13 ,a 2 =
a 1 = r 12Gρ 134 πr 13 ,a 2 = r
a 1 = r 12Gρ 134 πr 13 ,a 2 = r 2
a 1 = r 12Gρ 134 πr 13 ,a 2 = r 22
a 1 = r 12Gρ 134 πr 13 ,a 2 = r 22
a 1 = r 12Gρ 134 πr 13 ,a 2 = r 22 Gρ
a 1 = r 12Gρ 134 πr 13 ,a 2 = r 22 Gρ 2
a 1 = r 12Gρ 134 πr 13 ,a 2 = r 22 Gρ 2
a 1 = r 12Gρ 134 πr 13 ,a 2 = r 22 Gρ 23
a 1 = r 12Gρ 134 πr 13 ,a 2 = r 22 Gρ 234
a 1 = r 12Gρ 134 πr 13 ,a 2 = r 22 Gρ 234
a 1 = r 12Gρ 134 πr 13 ,a 2 = r 22 Gρ 234 πr
a 1 = r 12Gρ 134 πr 13 ,a 2 = r 22 Gρ 234 πr 2
a 1 = r 12Gρ 134 πr 13 ,a 2 = r 22 Gρ 234 πr 22
a 1 = r 12Gρ 134 πr 13 ,a 2 = r 22 Gρ 234 πr 22a
a 1 = r 12Gρ 134 πr 13 ,a 2 = r 22 Gρ 234 πr 22a 2
a 1 = r 12Gρ 134 πr 13 ,a 2 = r 22 Gρ 234 πr 22a 2 a
a 1 = r 12Gρ 134 πr 13 ,a 2 = r 22 Gρ 234 πr 22a 2 a 1
a 1 = r 12Gρ 134 πr 13 ,a 2 = r 22 Gρ 234 πr 22a 2 a 1
=
= ρ
= ρ 2
= ρ 2
= ρ 2 r
= ρ 2 r 2
= ρ 2 r 2
= ρ 2 r 2
= ρ 2 r 2 ρ
= ρ 2 r 2 ρ 1
= ρ 2 r 2 ρ 1
= ρ 2 r 2 ρ 1 r
= ρ 2 r 2 ρ 1 r 1
= ρ 2 r 2 ρ 1 r 1
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