Physics, asked by abhinash256, 11 months ago

The ratio of acceleration of blocks a placed on smooth incline with block b placed on rough

Answers

Answered by DreamBoy786
1

Answer:

Explanation:

for the smoothe surface, net downward force :f = mgsinθa = g sin45 = g2√for the rough surface:f = mg sinθ−fr = mgsinθ−μmgcosθa' = g⎛⎝⎜sinθ−μcosθ⎞⎠⎟ aa'=21g2√g(12√−μ2√) = 21=2−2μμ = 0.5

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