Question

The ratio of ages of sita and geeta is 4:3. the sum of their ages is 28 years. the ratio of their ages after 8 years will be ?

Answer 1

let the age of-
sita = x
geeta =y
x/y = 4/3
x = 4y/3
x+y = 28
4y/3 + y = 28
4y + 3y/3 = 28
7y = 28×3
y = 12
x = 28 - y
x = 16
their ages after 8 years
sita = 16 + 8
sita = 24
geeta = 12+8
geeta = 20
ratio:
24/20
=6/5

Answer 2

Answer:

Step-by-step explanation:

Sita : Geeta =4:3

The sum is 28 so

4x+3x=28 ......1 equation

So x=4 for solving

Put in 1 equation

Sita 16 year and Geeta 12 year old now

So after 8 year's become

Sita 16+8=24 and Geeta 12+8=20then

Ratio is 24/20 = 6/5

So answer is 6:5