Question

the ratio of altitude and base of a triangle is 1 ratio 2 and area is 9 square metre find its base and altitude​

Answer 1

▶ Question :-

→ The ratio of altitude and base of a triangle is 1 : 2 respectively and area is 9 m² . Find its base and altitude​ .


▶ Answer :-


→ Let the ratio be x .

i.e., altitude = x and base = 2x .


▶ Now,

We know that :-

$\sf \because area \: of \: triangle = \frac{1}{2} \times base \times height. \\ \\ \sf \implies 9 = \frac{1}{ \cancel2} \times \cancel2x \times x. \\ \\ \sf \implies9 = {x}^{2} . \\ \\ \sf \implies x = \sqrt{9} . \\ \\ \pink{ \sf \therefore x = 3m.}$


Therefore, altitude = x = 3m .


And, base = 2x = 2 × 3 = 6m .


✔✔ Hence, it is solved ✅✅.


THANKS

Answer 2

$<b>$Solution:-

Given:-

Area = 9 m^2.

The Ratio of Altitude & Base of Triangle :- 1 : 2.

Let the Altitude & Base be × & 2x respectively.

Now,

Area of Triangle =

$= > 9 = \frac{1}{2} \times base \times height \\ \\ = > 9 = \frac{1}{2} \times 2x \times x \\ \\ = > 9 \: = {x}^{2} \\ \\ = > x = \sqrt{9} \\ \\ = > x = 3$

Hence,

$\boxed{Base of the Triangle = 2x = 6 m.}$

$\boxed{Altitude of the Triangle = x = 3 m.}$