The ratio of an interior angle to be exterior angle of a regular polygon is 5: 1 find the number of sides of the polygon
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Answered by
3
Hi friend!!
Let 5x be the interior angle of a regular polygon and x be the exterior angle of a regular polygon.
Since the two angles are linear angles. Their sum is 180°
→5x+x=180
6x=180
x=30°
Interior angle of the regular polygon is 150° and exterior angle of the regular polygon is 30°
Interior angle of a n sided regular polygon is
2(n-2)×90/n=150
n-2/n=15/18
18n-36=15n
3n=36
n=12
The polygon is of 12 sides.
I hope this will help you;)
Let 5x be the interior angle of a regular polygon and x be the exterior angle of a regular polygon.
Since the two angles are linear angles. Their sum is 180°
→5x+x=180
6x=180
x=30°
Interior angle of the regular polygon is 150° and exterior angle of the regular polygon is 30°
Interior angle of a n sided regular polygon is
2(n-2)×90/n=150
n-2/n=15/18
18n-36=15n
3n=36
n=12
The polygon is of 12 sides.
I hope this will help you;)
Answered by
6
Heya Dear,
____________________________
Let x is included in the ratio.
Interior angle = 5 x.
Exterior angle = x.
We know that those angles will be pair of linear angles.
⇒ 5x + x = 180°
⇒ 6x = 180°
⇒ x = 180° / 6
∴ x = 30°.
Each interior angle = 5 x = 5 × 30° = 150°.
Each interior angle of a regular polygon = 2 ( n - 2 ) × 90° / n
⇒ 150° = 180° ( n - 2 ) / n
⇒ 150° n = 180° n - 360°
⇒ 180° n - 150° n = 360°
⇒ 30° n = 360°
⇒ n = 360° / 30°
∴ n = 12.
The required answer is 12.
Hope it helps !
____________________________
Let x is included in the ratio.
Interior angle = 5 x.
Exterior angle = x.
We know that those angles will be pair of linear angles.
⇒ 5x + x = 180°
⇒ 6x = 180°
⇒ x = 180° / 6
∴ x = 30°.
Each interior angle = 5 x = 5 × 30° = 150°.
Each interior angle of a regular polygon = 2 ( n - 2 ) × 90° / n
⇒ 150° = 180° ( n - 2 ) / n
⇒ 150° n = 180° n - 360°
⇒ 180° n - 150° n = 360°
⇒ 30° n = 360°
⇒ n = 360° / 30°
∴ n = 12.
The required answer is 12.
Hope it helps !
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