Question

the ratio of average speed of an O2 molecule To The RMS speed of N2 molecule at the same temperature is

Answer 1

The Average Speed of the Molecules is given by the Formula,

Vavg. = $\sqrt{\frac{8RT}{\pi M}}$

Now,

M is the Mass of the Oxygen = 32 g/mole.

Also, Vr.m.s. will be given by the Formula,

Vr.m.s. = $\sqrt{\frac{3RT}{m} }$

where m is the molar mass of the Nitrogen.

∴ Ratio of the Velocity Average and the Velocity r.m.s. = $\sqrt{\frac{8RT/M\pi }{3RT/m}}$

= $\sqrt{8m/3M\pi}$

= √[(8 × 28)/(3 × 32 × 22/7)]

=  √(1568/2112)

=  0.86/1

Hope it helps.

Answer 2

Answer:

Option varies, correct with your teaching and package

Explanation: