Question

The ratio of average translational kinetic energy to rotational

Answer 1

Answer:

Explanation:

For a diatomic molecule, the three translation direction contribute 1/2 kT per molecule, and for each molecule there are also two axes of rotation, contributing rotational kinetic energy in the amount of 1/2 kT each.

So total translational kinetic energy =(3/2)kT & total rotational kinetic energy =(2/2)kT.

So, the ratio of average translational kinetic energy to rotational kinetic energy of a diatomic molecule at temperature T is (3/2).

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Answer 2

total translational kinetic energy =(3/2)kT & total rotational kinetic energy =(2/2)kT. So, the ratio of average translational kinetic energy to rotational kinetic energy of a diatomic molecule at temperature T is (3/2).