the ratio of base and height of a triangle is 1:2, and its area is 49 sq.cms. find its base and height.
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Answered by
78
S O L U T I O N : -
Given ratio of base and height
= 1:2
Let us assume base and height like this
base = X
height=2X
Area of triangle= 1/2×base× height
According to question,
1/2×x×2x=49sq.cm
=49sq.cm
x=7 sq.cm
Base = 7 sq.cm (x)
Height=14 sq.cm(2x)
Anonymous:
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Answered by
16
Hola mate:☺As u asked for the question here is the answer ;
As in ∆triangle we know
Area=1/2×base×height.
So we have ratio of base n height and area so we can put it in formula discussed above:
So let:
Base =Bhv
N height=2Bhv
Formula;
49=1/2×bhv×2bhv
49=Bhv²
Bhv=+-7
So now put it in bhv
base=bhv=7 cms
Height=2bhv=7×2=14cms.
Extra gyan:
If you have any problem any query regarding any question in Mathematics then contact me.
Mark brainliest to my sw8 frnd Bhavna☺☺.
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As in ∆triangle we know
Area=1/2×base×height.
So we have ratio of base n height and area so we can put it in formula discussed above:
So let:
Base =Bhv
N height=2Bhv
Formula;
49=1/2×bhv×2bhv
49=Bhv²
Bhv=+-7
So now put it in bhv
base=bhv=7 cms
Height=2bhv=7×2=14cms.
Extra gyan:
If you have any problem any query regarding any question in Mathematics then contact me.
Mark brainliest to my sw8 frnd Bhavna☺☺.
Miss u yr.
Hit like
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