the ratio of base to height of a triangular field is 3:1.If the cost of cultivating field at ₹28 per sq.m is ₹9450,find its base and height
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Answered by
89
Let the height be a
Base = 3a
Cost of cultivating = Rs 9450.
Rate of cultivating = Rs 28 / m^2.
Area of field = Cost / Rate
Area of field = 9450 / 28
Base *Height /2 = 337.5 m^2
=> a * 3a = 675
=> 3a^2 = 675
=> a^2 = 225
=> a = 15 m
Height = 15 m
Base = 45 m
Base = 3a
Cost of cultivating = Rs 9450.
Rate of cultivating = Rs 28 / m^2.
Area of field = Cost / Rate
Area of field = 9450 / 28
Base *Height /2 = 337.5 m^2
=> a * 3a = 675
=> 3a^2 = 675
=> a^2 = 225
=> a = 15 m
Height = 15 m
Base = 45 m
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Answered by
34
let x is included in the ratio.
base= 3x.
height=x.
area of field= 1/2× 3x ^2 (eq. 1)
area of field=total cost of cultivating/cost of cultivation of per square meter
=rs. 9,450/rs.28 m ^2
= 675/2m ^2 (eq.2)
eq. 1=eq.2
675/2m ^2= 1/2* 3x ^2
x ^2=225m ^2
x= 15m.
base= 3x= 3×15m=45m
height=x= 15m
base= 3x.
height=x.
area of field= 1/2× 3x ^2 (eq. 1)
area of field=total cost of cultivating/cost of cultivation of per square meter
=rs. 9,450/rs.28 m ^2
= 675/2m ^2 (eq.2)
eq. 1=eq.2
675/2m ^2= 1/2* 3x ^2
x ^2=225m ^2
x= 15m.
base= 3x= 3×15m=45m
height=x= 15m
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