Question

The ratio of Boyle's temperature and critical temperature for a gas is

Answer 1

we know Boyle's temp. Tb = a/bR
and Critical temp. Tc = 8a/27Rb ..... [where a = volume correction and b = pressure correction, R= molar gas const.]

Therefore, Tb : Tc = 27 : 8

Hope u get ur answer.....

Answer 2

Answer : The ratio of Boyle's temperature and critical temperature for a gas is, 27 : 8

Explanation :

The formula used Boyle's temperature for a gas will be,

$T_b=\frac{a}{bR}$      .........(1)

where,

a = pressure correction factor

b = volume correction factor

R = gas constant

The formula used Critical temperature for a gas will be,

$T_c=\frac{8a}{27bR}$     ..........(2)

Now divide the equation (1) by equation (2), we get

$\frac{T_b}{T_c}=\frac{(\frac{a}{bR})}{(\frac{8a}{27bR})}\\\\\frac{T_b}{T_c}=(\frac{a}{bR})\times (\frac{27bR}{8a})\\\\\frac{T_b}{T_c}=\frac{27}{8}$

Therefore, the ratio of Boyle's temperature and critical temperature for a gas is, 27 : 8