Math, asked by Tanyachouhan8429, 1 year ago

The ratio of boys and girls in the class is 5:3.if 16%of boys and 8%of girls faild in a examination,then find the percentage of passed students

Answers

Answered by nath27076
40

Answer:

87% of the students passed the examination.

Step-by-step explanation:

Since we are given that the ratio of boys and girls in the class is 5:3,

∴ There are 5x boys in the class and 3x girls in the class.

Thus, the total number of students in the class is 8x.

It is given that 16% of the boys failed in the examination.

\frac{16}{100} * 5x = \frac{4}{25} *5x =<strong>\frac{20x}{25}

Again, it is mentioned that 8% of the girls failed.

\frac{8}{100} * 3x = \frac{2}{25}  * 3x = <strong>\frac{6x}{25}

Thus, the total number of failed students in the class is:

\frac{20x}{25} + \frac{6x}{25} = <strong>\frac{26x}{25}

Hence, the number of passed students = Total students - Failed students

= 8x - \frac{26x}{25}

= \frac{200x - 26x}{25} = \frac{174x}{25}

= 6.96x

Hence, out of 8x students, 6.96x students passed the examination.

Thus, the percentage of passed students is:

\frac{6.96x}{8x} * 100 = \frac{6.96}{8} * 100

= 0.87 * 100

=87%.

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