Question

The ratio of chromatids in a metaphasic chromosome and late anaphasic chromosome is​

Answer 1

A normal cell cycle comprises of interphase (G

1

phase, S phase and G

2

phase) and M phase. During the S phase of interphase, the DNA duplicates due to replication. The duplication of DNA leads to the production of two chromatids joined at the centromere. The M phase comprises of prophase, metaphase, anaphase and telophase. The chromatin material coils into distinct structures called chromosomes in the prophase. In the metaphase stage, chromosomes are arranged at the equator. Each chromosome comprises of two sister chromatids (produced due to DNA synthesis in the S phase) joined at the centromere. In the anaphase stage, the centromere splits and the two sister chromatids move to opposite poles.

So, the correct answer is option C.

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Answer 2

Answer:

The ratio is 2:1.

Explanation:

• The cell cycle is divided into two phases; Interphase (G1, S, and G2) and M-phase (Mitosis and cytokinesis).
• DNA replicates in the S-phase and is arranged as sister chromatids in a single chromosome.
• M-phase is followed by the interphase. Mitosis is divided into four phases; Prophase, Metaphase, Anaphase, and Telophase.
• Chromosomes are arranged on an equatorial plate in the metaphase. Sister chromatids remain attached in this phase.
• In the late anaphase, sister chromatids of a chromosome separate and completely migrated to the spindle poles.
• Hence, the ratio of chromatids in the metaphase chromosome to the late anaphase chromosome is 2:1.

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