the ratio of coordination number of Na+ and Cl- in face centered cubic lattice crystal of NaCl is
a)6:6
b)6:1
c)1:6
d)3:4
Answers
Answered by
3
The ratio of coordination no. of Na+ and Cl- in FCC lattice crystal of NaCl is 1:1.
hope this will help you...
hope this will help you...
KamalDubey:
For sodium chloride, Na+Cl-, there are 6 anions around each cation (coordination number Na = 6); because of the 1:1 stoichiometry there must also be 6 Na cations around each Cl anion.
Answered by
6
Hey there,
● Answer -
CN(Na):CN(Cl) = 6:6
● Explanation -
NaCl is an ionic solid existing in FCC structure.
Each Na cation is surrounded by 4 Cl anions in same plane, and 1 above & below each. i.e. CN = 4+1+1 = 6
Similarly, each Cl anion is surrounded by 4 Na cations in same plane, and 1 above & below each. i.e. CN = 4+1+1 = 6
Therefore, ratio of coordination numbers -
CN(Na) : CN(Cl) = 6 : 6
Hope this solved your query...
● Answer -
CN(Na):CN(Cl) = 6:6
● Explanation -
NaCl is an ionic solid existing in FCC structure.
Each Na cation is surrounded by 4 Cl anions in same plane, and 1 above & below each. i.e. CN = 4+1+1 = 6
Similarly, each Cl anion is surrounded by 4 Na cations in same plane, and 1 above & below each. i.e. CN = 4+1+1 = 6
Therefore, ratio of coordination numbers -
CN(Na) : CN(Cl) = 6 : 6
Hope this solved your query...
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