Question

The ratio of copper and zinc in an alloy is 4 : 3. Find the weight of each metal in the alloy whose weight is 413 g .
ANSWER WITH PROPER PROCESS....​

Answer 1

Answer:

the ratio is 4:3

10

* 4.0

let X be the common multiple of this ratio so the proportion of copper is 4x and proportion of zinc is 3x now the weight of alloy is given i.e. 413g

so we get,

4x + 3x = 413

7x = 413

X=413/7

X=59

3x = 59*3 = 177

4x = 59*4 = 236

so the proportion of copper is 236g and proportion of zinc is 177 g hope it is right and helpful

Answer 2

Answer

In 10 kg of 1st alloy the ratio of copper and zinc = 4:1

∴ Copper =54×10kg=8kg Zinc =51×10kg=2kg In 16 kg of 2nd alloy the ratio of copper and zinc = 1:3

∴ Copper =41×16kg=4kg Zinc =43×16kg=12kg

Let x kg be the amount of pure copper added Given Copper : Zinc = 3 : 2 in the new alloy, i.e. (8 + 4 + x) : (2 + 12) = 3 : 2

⇒1412+x=23⇒24+2x=42⇒2x=18⇒x=9kg

∴ Weight of the new alloy = (8 + 4 + 9 + 2 + 12) = 35 kg