The ratio of corresponding sides of two similar triangle is 16:25.Then find the ratio of their perimeter.
Answers
Answered by
51
Hi ,
If A1 , A2 are areas of two similar
triangles and p , P are their
corresponding perimeters then
( p/P )² = ( A1/A2 )
( p/P )² = 16/25 [ given ]
( p/P )² = ( 4/5 )²
p / P = 4/5
p : P = 4 : 5
I hope this helps you.
: )
If A1 , A2 are areas of two similar
triangles and p , P are their
corresponding perimeters then
( p/P )² = ( A1/A2 )
( p/P )² = 16/25 [ given ]
( p/P )² = ( 4/5 )²
p / P = 4/5
p : P = 4 : 5
I hope this helps you.
: )
Answered by
24
hence we know that
area = (perimeter)^2
let (p/P)^2=a1/a2
(p/P)^2=(16/25)
(p/P)=(16/25)
p/P=4/5
area = (perimeter)^2
let (p/P)^2=a1/a2
(p/P)^2=(16/25)
(p/P)=(16/25)
p/P=4/5
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