Physics, asked by shaziyakhursheed, 1 year ago

The ratio of displacement in n seconds to
second for a particle starting from rest and
uniform acceleration is
(1) 2n-1/n^2 (2)n-1/n (3)2n+1/2n-1 (4) n/n-1​

Answers

Answered by Princeashishkumar01
7

Answer:(2n-1)/n(square)

Explanation:

In n sec s=ut+1/2atsquate........ (1)

In nth second s=u+1/2a(2n-1).......... (2)

Ratio of nth to n seconds is

Dividing equation 2/1

(2n-1)/n(square)

Note u is zero here because body starts from rest!

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