Question

The ratio of distance of two satellites from the centre of earth is 1 : 4. The ratio of their time periods of rotation will be :

Answer 1

Answer:

Ratio b/w distance from to satellite= 1: 4

R1 = 1 x and R2 = 4x

According to Kepler's Third law the formula for time period of a satellite :

= (T1/ T2 )^2 = ( R1 /R2 ) ^3

= ( T1/ T2 )^2 = ( 1x / 4x ) ^3

= (T1/T2 )^2 = 1/64

= T1 / T2 = root ( 1/ 64 )

= T1/ T2 = 1/8

So , T1 = 1 hour

and

T2 = 8 hours

Hope it helps you!

pls mark brainliest!

Answer 2

Time period is not dependent on mass of satellite.

Time period(T) = 2π√r³/√GM ( M is mass of earth)

T² is directly proportional to r³

Therefore,

Ratio = r³/(2r)³

= r³/8r³

= 1:8