Question

the ratio of distances travelled by a body in 1 second, 2seconds and 3 seconds is​

Answer 1

Answer:

Using s = ut + 0.5at^2 where u = 0 and assuming a = 9.8m/s^2, in the first second the body will fall 0.5 x 9.8 x 1^2 = 4.9m

In 2 seconds, the body will fall 0.5 x 9.8 x 2^2 = 19.6m

In 3 seconds, the body will fall 0.5 x 9.8 x 3^2 = 44.1m

So, in the first second, 4.9m, in the second second, (19.9 - 4.9) = 14.7m and in the third second, (44.1 - 19.6) = 24.5m

4.9:14.7:24.5, or 1:3:5