Question

The ratio of Ed’s toy cars to Pete’s toy cars was initially 5:2. After Ed gave 30 toy cars to Pete, they each owned an equal number of toy cars. How many toy cars did they have altogether?

There were two answers to this in other asked questions but one was wrong and the other did not provide an explanation.

Answer 1

Answer:The ratio of Ed's car was 5:2 at first. After Ed gave 30 cars to Pete, they each owned an equal amount of cars. How many cars did they have altogether.

I solve the problem but the answer seem wrong when I retest. here is my equation:

5:2

5x - 30= 2x (because Ed gave 30 cars to P : 5x-30)

5x -2x = 30

3x= 30

x= 10

Then I retest x=10 but the number was wrong 50:20 but Ed gave 30 cars to Pete.

---------------------

===========================

=============================

5:2

5x-30 = 2x+30

3x = 60

x = 20

------------

Ed had 5*20 = 100 cars

Pete had 2*20 = 40 cars

============================

Cheers,

hazzoki

Step-by-step explanation:

Answer 2

Given:

Ratio of Ed's toy cars to Pete's toy cars = 5:2

No. of cars given by Ed to Pete = 30

After giving 30 cars, they have same no. of cars.

To find:

No. of cars Pete and Ed have together.

Solution:

Let Ed be represented as E and Pete be represented as P.

$E:P=5:2$

When Ed gives 30 toy cars to Pete, both have same no. of toy cars.

Let $x$ be the no. of toy cars.

$2x+30=5x-30$

$5x-2x=30+30$

$3x=60$

$x=20$

Hence, initially Ed had $5$×$20=100$ toy cars

and Pete had $2$×$20=40$ toy cars

Total cars = $100+40=140$ toy cars

Pete and Ed altogether had 140 toy cars.