Question

The ratio of Hydrogen and oxygen in water is 1:8, find the quantity of oxygen in 72 litres of water​

Answer 1

Step-by-step explanation:

Given :-

The ratio of Hydrogen and oxygen in water is 1:8

To find :-

The quantity of oxygen in 72 litres of water.

Solution :-

Given that

The ratio of Hydrogen and oxygen in water = 1:8

Let they be X litres and 8X litres

The quantity of Hydrogen = X litres

The quantity of Oxygen = 8X litres

Total quantity of both Hydrogen and Oxygen in the water = X+8X = 9X litres

Given that

The quantity of water = 72 litres

Therefore, 9X = 72

=> X = 72/9

=> X = 8 litres

Therefore, The quantity if Hydrogen = 8 litres

The quantity of Oxygen = 8X litres

=> 8×8 = 64 litres

Answer :-

The quantity of Oxygen in 72 litres of water is 64 litres

Answer 2

Information mentioned in above question :

• The ratio of Hydrogen and oxygen in water is 1:8

What we have to find out :

• The required quantity of oxygen in 72 litres of water

We know that :

Mass of 1 Hydrogen atoms

• ➡ 1 gram

Mass of an Oxygen atoms

• ➡ 16 gram

Mass of two Hydrogen atoms

$\rm \implies \: 2 \times 1 \: gram = 2 \: gram$

Mass of 1 Oxygen atoms

$\rm \implies \:1 \times 16 \: gram \: = \: 16 \: gram$

On adding all the above-obtained values we get,

➡ Mass of water

$\rm \implies 2 \: gram + 16 \: gram = 18 \: gram$

Calculation :

$\displaystyle\implies \rm \dfrac{16}{18} \times 72$

$\displaystyle\implies \rm \dfrac{16 \times 72}{18}$

$\displaystyle\implies \rm \dfrac{1152}{18}$

$\bf\implies 64$