the ratio of iñcomes of two people is 9 : 7 and the ratio of the their expenditures is 4 : 3. If each of them manages to save ₹ 2000 per month, find their monthly income.
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Answered by
14
Here is your solutions
Given :-
Ratio of their incomes is 9:7 and expenditure is 4:3 .
let their incomes be 9xand 3y
Expenditures be 7x and 3y
first person savings:-
9x-4y=2000......................(1)
second person saving :-
savings=7x-3y=2000.....................(2)
from 1and 2 equations we get
x=2000 and y=4000
income of first person=18000
income of second person=14000
Hope it helps you
Given :-
Ratio of their incomes is 9:7 and expenditure is 4:3 .
let their incomes be 9xand 3y
Expenditures be 7x and 3y
first person savings:-
9x-4y=2000......................(1)
second person saving :-
savings=7x-3y=2000.....................(2)
from 1and 2 equations we get
x=2000 and y=4000
income of first person=18000
income of second person=14000
Hope it helps you
Answered by
10
Hey there!
________________________↓
Let the common ratio of their incomes be x ,
so their income now becomes 9x and 7x.
and let the common ratio of their. savings be y
so their income now becomes 4y and 3y
According to question:-
Savings of both are ₹2000 per month
so , saving of first person = >
9x-4y=2000....................1)
and saving of second person =>
7x-3y=2000. ...............2)
Multiplying 1) by 3 and 2) by 4 we get,
27x-12y=6000. .............3)
28x-12y=8000. ............. 4)
Subtracting 3)from 4) we get,
x=₹2000 and y=₹7000
hence ,
Monthly income of first person =9x=9×2000=₹18000
Monthly income of second person=7x=7×2000=₹14000
Thanks
_______________
________________________↓
Let the common ratio of their incomes be x ,
so their income now becomes 9x and 7x.
and let the common ratio of their. savings be y
so their income now becomes 4y and 3y
According to question:-
Savings of both are ₹2000 per month
so , saving of first person = >
9x-4y=2000....................1)
and saving of second person =>
7x-3y=2000. ...............2)
Multiplying 1) by 3 and 2) by 4 we get,
27x-12y=6000. .............3)
28x-12y=8000. ............. 4)
Subtracting 3)from 4) we get,
x=₹2000 and y=₹7000
hence ,
Monthly income of first person =9x=9×2000=₹18000
Monthly income of second person=7x=7×2000=₹14000
Thanks
_______________
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