The ratio of incomes of two persons is 5: 3 and that of their expenditures is 9: 5. If they save Rs. 2000 and Rs. 1500 respectively, their expenditure are?
(a) Rs. 6750, Rs. 3750
(b) Rs. 6000, Rs. 3600
(c) Rs. 10000, Rs. 6000
(d) Rs. 9000, Rs. 5400
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10.The ratio of incomes of two persons is 5 : 3 and that of their expenditures is 9 : 5. If they save Rs, 2600 and Rs. 1800 respectively, their incomes are :
(1) Rs. 8000; Rs. 4800
(2) Rs. 6000; Rs. 3600
(3) Rs. 10000; Rs. 6000
(4) Rs. 9000; Rs. 5400
Answers and Solution:
1. (2)
Number = 269*68
= 269 * (67+1)
= 269 * 67 + 269
clearly,remainder is obtained on dividing 269 by 67 that is 1.
2. (4)
Let x+y = 20 and x-y = 8
S0 (x+y)(x-y) = 20*8
=> x^2-y^2 = 160
3. (2)
Here x*y = 3x+2y
so 2*3+3*4 = (3*2+2*3)+(3*3+2*4)
= 12+17=29
4. (1)
Let the number of students be x.then,
=> 7 = (x*6+12*40)/(x+12)
=7x + 84 = 6x + 480
=> x = 396
5. (2)
6. (3)
10% of A = 15% 0f B = 20* 0f C
=> 10A = 15B = 20C
=> 10A/60 = 15B/60 = 20C/60
=> A/6 = B/4 = C/3
So A : B : C = 6 : 4 : 3
so 6x + 4x + 3x = 7800
=> 13x = 7800
x = 600
B's income = 4x = 600*4 = 2400
7.(2)
8. (4)
9. (1)
10. (1)
Let the incomes of two persons be Rs.5x and 3x rupess and their expenditure be Rs.9x and 5x respectively,
As given
5x - 9y = 2600.......(1)
3x - 5y = 1800.......(2)
by solve
then, x = 1600
So First person's income = 1600*5 = 8000
Second's person income = 1600*3 = 4800
(1) Rs. 8000; Rs. 4800
(2) Rs. 6000; Rs. 3600
(3) Rs. 10000; Rs. 6000
(4) Rs. 9000; Rs. 5400
Answers and Solution:
1. (2)
Number = 269*68
= 269 * (67+1)
= 269 * 67 + 269
clearly,remainder is obtained on dividing 269 by 67 that is 1.
2. (4)
Let x+y = 20 and x-y = 8
S0 (x+y)(x-y) = 20*8
=> x^2-y^2 = 160
3. (2)
Here x*y = 3x+2y
so 2*3+3*4 = (3*2+2*3)+(3*3+2*4)
= 12+17=29
4. (1)
Let the number of students be x.then,
=> 7 = (x*6+12*40)/(x+12)
=7x + 84 = 6x + 480
=> x = 396
5. (2)
6. (3)
10% of A = 15% 0f B = 20* 0f C
=> 10A = 15B = 20C
=> 10A/60 = 15B/60 = 20C/60
=> A/6 = B/4 = C/3
So A : B : C = 6 : 4 : 3
so 6x + 4x + 3x = 7800
=> 13x = 7800
x = 600
B's income = 4x = 600*4 = 2400
7.(2)
8. (4)
9. (1)
10. (1)
Let the incomes of two persons be Rs.5x and 3x rupess and their expenditure be Rs.9x and 5x respectively,
As given
5x - 9y = 2600.......(1)
3x - 5y = 1800.......(2)
by solve
then, x = 1600
So First person's income = 1600*5 = 8000
Second's person income = 1600*3 = 4800
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