The ratio of incomes of two persons is 9:7 and the ratio of their expenditures is 4:3. If each of them saves Rs 20 per month. Find their monthly incomes.
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●let their income be in ratio 9x and 7x and expenditure be 4y and 3y.
savings of each peson is 20 Rs.
savings=income-expenditure,so
20= 9x-4y
20= 7x-3y
=> 9x-4y=20...(i)
=> 7x-3y=20...(ii)
multiplying eq.(i) by 3 and eq(ii) by 4
=> 27x-12y=60 ...(iii)
=> 28x-12y=80...(iv)
subtracting eq(iv) from eq.(iii) we get,
-x = -20
or x = 20
●so now monthly income of 1 personis 9x=9(20)= 180
● and monthly income of second person is 7x=7(20)= 140....
_________________________
HOPE IT HELPS U DEAR! !!!!
HAVE A SWEET MORNING ☺☺
# Nikky
________________________
●let their income be in ratio 9x and 7x and expenditure be 4y and 3y.
savings of each peson is 20 Rs.
savings=income-expenditure,so
20= 9x-4y
20= 7x-3y
=> 9x-4y=20...(i)
=> 7x-3y=20...(ii)
multiplying eq.(i) by 3 and eq(ii) by 4
=> 27x-12y=60 ...(iii)
=> 28x-12y=80...(iv)
subtracting eq(iv) from eq.(iii) we get,
-x = -20
or x = 20
●so now monthly income of 1 personis 9x=9(20)= 180
● and monthly income of second person is 7x=7(20)= 140....
_________________________
HOPE IT HELPS U DEAR! !!!!
HAVE A SWEET MORNING ☺☺
# Nikky
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