Question

the ratio of intensities at minima to the maxima in the young's double slit experiment is 9:25. find the ratio of width of the two slits.

Answer 1

I min : I max = ( i1 ^½ - i2^½)²:(i1^½ + i2^½)² = 9:25
So, (i1^½ - i2^½)/(i1^½ +i2^½) =3/5 = (4-1)/(4+1)
So i1 = 4² =16
__i2 = 1² =1
Ratio of width w1 :w2 = i1:i2 =16:1
Hope this is ur required answer.

Answer 2

here is your answer mate..