Question

The ratio of length of each equal side and the third side of an isosceles tri angle is 3:4.If the area of the tri angle is 18√5sq unite,the third side is;???​

Answer 1

$given \\ ratio \: of \: each \: equal \: side \\ \: of \: third \: side = 4 \div 3$

$area \: of \: traingle \: = 18 \sqrt{5}$

area of triangle = base*hight/2

hight = sqrt(9x^2 - 4x^2 )

there for

sqrt(9x^2 - 4x^2)*2x/2 = 18/sqrt5

squering both side

5x^4 = 18^2/5

x^4 = 3^4 *2^2/5^2

x = 3 sqrt(2/5)

so third side = 12sqrt(2/5)