The ratio of length of man and length of his shadow is 9:5 . find the height of his shadow , if height of man is 720 cm
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Answer:
Let AB be the lamp post
and let MN be the man of height 2m
and let AM=lmeter.
and MS is the shadow of the man.
Let length of shadow MS=s
Given: Man walks at speed of 5kmph
∴ dt/dl =5kmph
We need to find rate at which the length of his
shadow increases= dt/ds
In △ASB,tanθ= AS/AB = l+s6....(1)
In △MSN,tanθ= MS/MN = s2 ....(2)
From (1) and (2)
l+s6 = s2
⇒6s=2l+2s
⇒4s=2l or l=2sdt/dl =2 dtds5=2 dtds since given that dt/dl =5kmph
∴ dt/ds = 25 kmph=2.5kmph
Step-by-step explanation:
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