the ratio of length to breadth of a rectangular field is 4 is to 3 if diagonal is 200 the area of the field in square metres is
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Answered by
25
Given :-
- The ratio of length to breadth of a rectangular field is 4 : 3 if diagonal is 200m
To find :-
- Area of the field in m²
Solution :-
Let the length be 4x and breadth be 3x
- Diagonal of rectangle = 200m
As we know that
→ D = √l² + b²
Where " D " is diagonal, " l " is length and " b " is breadth.
As per given condition
→ D = √l² + b²
→ 200 = √(4x)² + (3x)²
→ 200 = √16x² + 9x²
→ 200 = √25x²
→ 200 = 5x²
→ x² = 200/5
→ x² = 40
→ x = √40
→ x = 6.32m approx
Hence,
- Length of rectangle = 4x = 25.28m
- Breadth of rectangle = 3x = 18.96m
Now,
→ Area of rectangle
→ Length × breadth
→ 25.28 × 18.96
→ 25.2 × 18.9
→ 476.28m²
Answered by
163
GIVEN:-
__________
- The ratio of length and breadth of
- a rectangular field is 4:3
- The diagonal of the rectangular field = 200 m
TO FIND:-
____________
- What is the area of the field?
SOLUTION:-
______________
- Let 'x' be the common in given ratios
- Length= 4x
- Breadth= 3x
- To find the Length and breadth of
- the rectangular field, we use the Pythagoras theorem
- (Hypotenuse)² = (Base)?+ (Perpendicular)²
- (200)={4x)5 + (3x)4
- 40000 =16x+9x
- 40000 = 25x2
- 40000x²+25-x 1600
x=40m
- Length= 4x = 4(40) = 160
- Breadth- 3x = 3(40) = 120
- Now, we have to find the area of the field
- the area of the rectangular field,
- We use the formula:-
- Area of Rectangle = Length x+Breadth
According to question
- Area = 160 x 120
- Area = 19200 m2
___________________________________
Hence, the area of rectangular field is 19200 m2
_________________________________
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