The ratio of milk and water in a vessel is 5:3. how much part of a mixture is replaced by 1/10 of its part by water so that the ratio of new mix becomes 1:1
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Let us assume that he vessel contains x litres of mixture
Initial ratio of milk to water is = 5 : 3
Total parts = 5+3 = 8
After replacing New ratio of milk to water in mixture is 1 : 1
Let y litre of mixture is drawn out and y/10 water is added.
In new mixture, amount of milk will be: 5x/8 – 5y/8
In new mixture, amount of water will be:
new ratio = (5x/8 – 5y/8) / (3x/8 – 3y/8 + y/10)= 1
5x/8 – 5y/8 = 3x/8 – 3y/8 + y/10
2x/8 = 2y/8 + y/10
2x = 2y + (8y /10)
2x = 28 y /10
x = 28y/20
y/x = 20/28 = 5/7
So, to make the water and milk ratio as 1:1, we must replace 5/7 part of mixture with 1/10 part of it by water.
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Answer: 5/7
Explanation:
See short trick in attached photo
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