Chemistry, asked by IBRAHIM1272, 1 year ago

The ratio of milk and water in a vessel is 5:3. how much part of a mixture is replaced by 1/10 of its part by water so that the ratio of new mix becomes 1:1

Answers

Answered by Answers4u
18

Let us assume that he vessel contains x litres of mixture

Initial ratio of milk to water is = 5 : 3

Total parts = 5+3 = 8

After replacing New ratio of milk to water in mixture is 1 : 1

Let y litre of mixture is drawn out and y/10 water is added.

In new mixture, amount of milk will be: 5x/8 – 5y/8

In new mixture, amount of water will be:

new ratio = (5x/8 – 5y/8) / (3x/8 – 3y/8 + y/10)= 1

5x/8 – 5y/8 = 3x/8 – 3y/8 + y/10

2x/8 = 2y/8 + y/10

2x = 2y + (8y /10)

2x = 28 y /10

x = 28y/20

y/x = 20/28 = 5/7

So, to make the water and milk ratio as 1:1, we must replace 5/7 part of mixture with 1/10 part of it by water.


Answered by bakchodiya
2

Answer: 5/7

Explanation:

See short trick in attached photo

Attachments:
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