Question

The ratio of milk to water in a mixture is 4:3.146 litres of water is added to this mixture, the ratio of milk



water becomes 8: 7. What is the quantity of milk in the original mixture?

Answer 1

Given that the ratio of milk and water in a mixture = 4 : 3

let the constant ratio be 'x'

so now let the quantity of milk and water be 5x L and 3x L

since , given that 146 litre (L) water was added to the mixture , so now

Find new quantity of water in the mixture:
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new quantity of water =( 3x + 146 ) L

according to question

after adding 146L water in the mixture then new ratio of milk and water is 8 : 7

4x : (3x + 146) = 8 : 7

4x /(3x + 146) = 8 / 7

7 × 4x = 8 ( 3x + 146 )

28x = 24x + 1168

28x - 24x = 1168

4x = 1168

x = 292

quantity of milk in the original mixture

=4x = 4 × 292 = 1168 L

therefore ,
quantity of milk in the original mixture
= 1168 litre
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Your Answer : milk = 1168 litre
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Answer 2

M:W=4:3...(1)

When 6L is added to the mixture

$⇒ \frac{M}{W+6} = \frac{8}{7}$

⇒7M=8W+48...(2)

From Eq(1)

$M= \frac{4W}{3}$

putting value of M in (2)

$⇒7 \frac{4W}{3} =8W+48$

$⇒W=36$

Using

$⇒ M= \frac{4W}{3}$

⇒M=48