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The ratio of minimum to maximum wavelength of radiation

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Answered by Faraaz17
1

Explanation:

Q)

The ratio of minimum to maximum wavelengths of radiation that an electron cause in Bohr's hydrogen atom is

(a)12(b)zero(c)34(d)2732(a)12(b)zero(c)34(d)2732

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A)

Answer : (c) 3434

Explanation :

Energy of realiation that corresponds to energy difference between two energy levels n1n1 and n2n2 is given as

ε=13.6(1n21−1n22)eVε=13.6(1n12−1n22)eV

εε is minimum when n1=1n1=1 & n2=2n2=2

εmin=13.6(1−14)eVεmin=13.6(1−14)eV

=13.6×34eV=13.6×34eV

εε is maximum when n1=1n1=1 & n2=∞n2=∞ (the atom is ionized , thatt is known as ionization energy )

εmax=13.6(1−1∞)=13.6eVεmax=13.6(1−1∞)=13.6eV

εminεmax=34→hcλmaxhcλminεminεmax=34→hcλmaxhcλmin

λminλmax=34.

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