The ratio of mole of H, and CH, in a mixture having equal mass of both is
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See, Let's assume a container, with equal mass of CH and H, say, "x" grams.
We, know from the concept of moles,
no. of moles of any substance= (Given mass) / (Molar Mass)
1. Moles of CH in the container, = x/13 (Molar Mass = 12+ 1 )
2. Moles of H in the container= x/ 1
Now, we are required to find a ratio of equations 1 and 2,
So,Ratio comes out to be= 1/13.
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