The ratio of monthly income of A and B in the ratio is 6:5 and the ratio of their expenditure is 9:7.If each saves Rs.1500.Then the sum of their salary is
Answers
GIVEn
The ratio of monthly income of A and B in the ratio is 6:5 and the ratio of their expenditure is 9:7.If each saves Rs.1500.
TO FINd
Find the salary of A and B
SOLUTIOn
✞ Let the income of A be 6x and B be 5x Now, let their expenditure be 9y and 7y
✑ According to the given condition
- Income = Expenditure + Saving
- 6x = 9y + 1500 { For A }
- 5x = 7y + 1500 { For B }
→ 6x - 9y = 1500 ---(i)
→ 5x - 7y = 1500 -----(ii)
✑ Multiply (i) by 5 and (ii) by 6
- 30x - 45y = 7500
- 30x - 42y = 9000
✑ Subtract both the equations
→ (30x - 45y) - (30x - 42y) = 7500 - 9000
→ 30x - 45y - 30x + 42y = -1500
→ - 3y = -1500
→ y = 1500/3 = 500
✑ Put the value of y in eqⁿ (ii)
→ 5x - 7y = 1500
→ 5x - 7×500 = 1500
→ 5x - 3500 = 1500
→ 5x = 3500 + 1500
→ 5x = 5000
→ x = 5000/5 = 1000
Hence,
Salary of A = 6x = 6 × 1000 = Rs.6000
Or
Salary of B = 5x = 5×1000 = Rs.5000
- Ratio of income of A and B = 6:5
- Ratio of expenditure of A and B = 9:7
- Sum of their salary
Let the ratio of their :-
- Income = 6x : 5x
- Expenditure = 9y : 7y
Now,
➠ 6x - 9y = 1500 ------➀
➠ 5x - 7y = 1500. -------➁
On multiplying Eq. (i) by 5 and Eq. (ii) by 6 to make the coefficients of x equal, we get
➠ 30x – 45y = 7500 …(3)
➠ 30x – 42y = 9000 …(4)
On subtracting Eq. (3) from (4), we get
↣ (30x - 42y) - (30x - 45y) = 9000 - 7500
↣ 10x - 10x - 42y + 45y = 1500
↣ 3y = 1500
↣ y = 500
On putting y = 500 in Eq. (1) , we get
↣ 6x – 9y = 1500
↣ 6x - 9×500 = 1500
↣ 6x - 4500 = 1500
↣ 6x = 1500 + 4500
↣ 6x = 6000
↣ x = 6000/6
↣ x = 1000
Thus,
Monthly income of both the persons are 6(1000) and 5(1000), i.e. Rs. 6000 and Rs. 5000
- Sum of their salary = 6000 + 5000 = 11000