The ratio of non metal atoms to the number of atoms of non metallic oxides A and B are 0.33 and 0.25 respectively. Find the valencies of non metals present in those metallic oxides
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The valency of non metal is +4 and the valency of non metallic oxide is +8.
Explanation:
Given ratio= 0.33 i.e. 1:3
- So, there is 1 non metal atom out of 3 atoms of the molecule
- Therefore, out of 3 atoms, if 1 is non metal, the other 2 will have to be oxygen atoms, since it's given the compound is an OXIDE
- Finally, we see that, we have 1 non-metal atom for every 2 oxygen atoms
Hence the valency of that 1 non-metal atom must be equal to the total valence of the 2 oxygen atoms (∵ total valence of a compound = 0)
- Let the valency of non-metal be x.
We know the valency of each Oxygen atom = -2
For compound, total valence = x + (2 x (-2)) = 0
x - 4 = 0
x = +4
Hence, valency of the non-metal ion is +4
- For B:
It's the same thing, but with ratio 1:4 (which is equal to 0.25)
so, x + (4 x (-2)) = 0
x - 8 = 0
x = +8
Hence the valency of non metal is +4 and the valency of non metallic oxide is +8.
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