Question

the ratio of non-metal atoms to the number of atoms of two non metallic oxide A and B are 0.33 and 0.25 respectively.find the valencies of non metal present in those metallic oxides

Answer 1

The valencies of oxides A and B is +4 and +8 respectively.

Explanation:

• The valency of that 1 non-metal atom must be equal to the total valence of the 2 oxygen atoms (Total valence of a compound = 0)
• Let the valency of non-metal be x.
• We know the valency of each Oxygen atom = -2

For compound, total valence = x + (2 x (-2)) = 0

x - 4 = 0

x = +4

Hence, valency of the non-metal ion is +4

For B:

The ratio is 1:4 (which is equal to 0.25)

so, x + (4 x (-2)) = 0

⇒ x - 8 = 0

⇒ x = +8

Thus the valencies of oxides A and B is +4 and +8 respectively.

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Why is it SO2 as sulphur valency is 2 and oxygen valency is also two then why are they not cancelling each other and why it's not only SO?

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