Question

The ratio of number of molecules in equal
weights of H2, He and CH4​

Answer 1

Answer:

Ratio between the molecules in equal mass CH4,O2,SO2 is 4:2:1 .

Answer 2

Answer:

The ratio of the number of molecules of $H_{2} : He: CH_{4}$ at equal masses are $8:4:1$.

Explanation:

Given,

The mass of $H_{2}$, $He$, $CH_{4}$ is equal.

The ratio of the number of molecules =?

Let equal mass = x g

As we know,

• The number of moles = $\frac{Mass}{Molar mass}$

Now,

• The molar mass of $H_{2}$ = $2\times 1$ = $2 g/mol$
• The molar mass of $He$ = $4g/mol$
• The molar mass of $CH_{4}$ = $12 + 4(1)$ = $16g/mol$

Now,

• The number of moles of $H_{2}$ = $\frac{x}{2} mol$
• The number of moles of $He$ = $\frac{x}{4}mol$
• The number of moles of $CH_{4}$ = $\frac{x}{16} mol$

As we know,

• 1 mole = $6.022 \times 10^{23}$ molecules

For $H_{2}$,

• $\frac{x}{2}$ mole = $\frac{x}{2} \times 6.022 \times 10^{23}$ = $3.011x\times 10^{23}$ molecules

For $He$,

• $\frac{x}{4}$ mole = $\frac{x}{4}\times 6.022 \times 10^{23}$= $1.505x \times 10^{23}$ molecules

For $CH_{4}$,

• $\frac{x}{16}$ mole = $\frac{x}{16} \times 6.022 \times 10^{23}$ = $0.376x \times 10^{23}$ molecules

Thus, the ratio of the number of molecules is:

• $H_{2} : He: CH_{4}$ = $3.011x\times 10^{23} : 1.505x \times 10^{23}: 0.376x \times 10^{23}$
• $H_{2} : He: CH_{4}$ = $8: 4 : 1$

Hence, the ratio of number of molecules of $H_{2} : He: CH_{4}$ at equal masses are $8: 4 : 1$.