The ratio of parallel side of a trapezium is 4 :5. The distance between than is 15 cm. If the area of the trapezium is 405 sq. Cm, fin
d the length of the base.
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let the common multiple be x so one parallel side=4x and other parallel side =5x
a(trapezium)=1/2×(sum of length of parallel sides)×height
405=1/2(4x+5x)×15
405÷15=1/2×9x
27=4.5x
x=270/45
x=6cm
one parallel side=4x=4×6=24cm
other parallel side=5x=5×6=30cm
so,the length if the base is 30cm
a(trapezium)=1/2×(sum of length of parallel sides)×height
405=1/2(4x+5x)×15
405÷15=1/2×9x
27=4.5x
x=270/45
x=6cm
one parallel side=4x=4×6=24cm
other parallel side=5x=5×6=30cm
so,the length if the base is 30cm
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