Question

The ratio of ph of 0.1 m h2so4 and that of 0.1 n h2so4 is

Answer 1

The condition before neutralization,

mili moles of HCl = 50 * 0.4 = 20

mili moles of NaOH = 50 * 0.2 = 10

Following is the situation after neutralization,

mili moles of NaOH = 0

mili moles of HCl = 10

Now, HCl gets dissociated into H+ and Cl-

Further, H+ concentration = 10/100 = 0.1 M ( as the volume of the solution is 100 ml).

Hence, by formula,

ph = - log (H+)

So, we get pH = 1, which is the answer.

Answer 2

Answer:

7:10

Explanation:

Refer to attachment