Math, asked by sakshim1816, 18 days ago

The ratio of present age of father to that of son is7:2. After 10 years their ages will be in a ratio of 9:4. The present age of the father is?

Answers

Answered by sd285223
0

Answer:

Let the present ages of father and son be 7x and 2x

after 10 years:

father's age=7x+10

son's age=2x+10

ATQ,

7x+10:2x+10=9:4

=>28x+40=18x+90

=>10x=50

=>x=5

Thus, present age of father=7x=7*5=35years

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Answered by bhagatramjee9
1

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